Question

$16 \times 2 {}^{n + 1} - 4 \times 2 {}^{n} \div 16 \times 2 {}^{n + 2} - 2 \times 2 {}^{n + 2 }$

Answer 1

$\textbf{ Hello Mate! }$


$\frac{16 \times {2}^{n + 1} - 4 \times {2}^{n} }{16 \times {2}^{n + 2} - 2 \times {2}^{n + 2} } \\ \frac{16 \times {2}^{n} \times 2 - 4 \times {2}^{n} }{16 \times {2}^{n} \times {2}^{2} - 2 \times {2}^{n} \times {2}^{2} } \\ = \frac{ {2}^{n}(16 \times 2 - 4) }{ {2}^{n}(16 \times 4 - 2 \times 4) } \\ = \frac{32 - 4}{64 - 8} = \frac{28}{56} \\ on \: cancelling \: we \: get \\ = \frac{1}{2}$
$\boxed{ Answer : 1 / 2 }$

Have great future ahead!