Question

$16 {x}^{2} - 3 = (2x + 3)(5x - 4) \: is \: it \: quadratic \: equation$
​

Answer 1

Answer:

16x²-3=(2x+3)(5x-4)

16x²-3=10x²-8x+15x-12

16x²-3=10x²+7x-12

16x²-10x²+7x-3+12=0

6x²+7x+9=0

hope it helps you and Don't forget to follow mè

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

➙16x²-3= (2x+3)(5x-4)

➙16x²-3= 2x(5x-4)+3(5x-4)

opening the brackets and expanding the terms

➙16x²-3= 10x²-8x+15x-12

➙16x²-3= 10x²+7x-12

Making like terms together

➙16x²-10x²-7x-3+12

➙6x²-7x+9

The Equation we obtained is in the form of ax²+bx+c which is the general form of a quadratic equation.Hence,it satisfied the Equation and therefore,it is a quadratic equation.

=>Further solve

➙6x²-7x+9

a= 6,b= -7 , c= 9

It can be solve through quadratic formula

x= -b±√b²-4ac ÷ 2a

➙x= -(-7)±√ (-7)²-4(6)(9)/2(6)

➙x= 7±√49-216/12

➙x= 7±√-167/12

Here,the discriminant is >0

So,there are two complex roots

➙x= 7±√167i /12

➙x=7/12±√167i/12

➙x= 0.58+1.07i

➙x= 0.58-1.07i