Math, asked by prisha12328, 1 year ago


16 {x}^{4}  -  {x}^{2}  + 2xy -  {y}^{2}

Answers

Answered by gautamkumar118
1

Step-by-step explanation:

 = 16 {x}^{4}  -  {x}^{2}  + 2xy  - {y}^{2}  \\  =  16 {x}^{4}  - ( {x}^{2} - 2xy +  {y}^{2}  ) \\  = 16 {x}^{4}  - (x - y)^{2}  \\  =  {(16 {x}^{ {2} }) }^{2}  -  {(x - y)}^{2}  \\  = (16 {x}^{2}  - x + y)(16 {x}^{2}  + x - y) \\  \\

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