Question

$16 {x}^{4} - {x}^{2} + 2xy - {y}^{2}$
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Answer 1

Step-by-step explanation:

$= 16 {x}^{4} - {x}^{2} + 2xy - {y}^{2} \\ = 16 {x}^{4} - ( {x}^{2} - 2xy + {y}^{2} ) \\ = 16 {x}^{4} - (x - y)^{2} \\ = {(16 {x}^{ {2} }) }^{2} - {(x - y)}^{2} \\ = (16 {x}^{2} - x + y)(16 {x}^{2} + x - y)$

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