Math, asked by ranjitpinky7483, 9 months ago

$16a {}^{2} b - 64b {}^{3}$
Factorise using identity

Answers

Answered by Anonymous

1

16a²b - 64b³

= 16b(a²-4b²)

= 16b[(a)²-(2b)²]

= 16b(a²-2b²)

= 16b(a+2b)(a-2b)

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