Question

$({ - 18})^{3} + ({12})^{3} + ({6})^{3}$
​

Answer 1

Answer :

$\large \red{ \sf - 3888}$

Explanation :

Given :

$( - 18 {}^{3}) + ({12}^{3}) + ( {6}^{3} )$

Formula used :

$(a + b + c) {}^{3} = \bf {a}^{3} + {b}^{3} + {c}^{3} - 3abc$

Equations :

so,

$if \: (a + b + c) = \bf0$

then,

${a}^{3} + {b}^{3} + {c}^{3} = \bf3abc$

Here,

$( - 18 + 12 + 6) = \bf0$

So,

$( - 18) {}^{3} +( {12}^{3}) + ({6}^{3} ) = \bf 3( - 18)(12)(6)$

$\huge \red{ \sf = - 3888}$