Question

(
$(2)^0 + (3)^0 4 ^0{?}$
plz give answer plz



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Answer 1

Answer:

It's very simple

By BODMAS rule

BODMAS rule is

B= bracket

O=Of

D=divide

M=multiplication

A=addition

S=subtraction

So by BODMAS rule in this que we have to multiply first

=1×0+2×0+3×0+4×0+5×0

=0+0+0+0+0

So ans is 0

Step-by-step explanation:

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Answer 2

Answer:

2^0 = 1

anything raised to the power zero is 1

so , the given expression becomes 1+1 =2

HOPE THIS HELPS YOU...