Question

(
$({2}^{ - 1} + {4}^{ - 1} + {6}^{ - 1} + {8}^{ - 1} ) {x} = 1$
find the value of x ​

Answer 1

Step-by-step explanation:

$(1 \div 2 + 1 \div 4 + 1 \div 6 + 1 \div 8) \times x = 1 \\ (25 \div 24)x = 1 \\ x = 24 \div 25$