Question

${2}^{ - 1} + {4}^{ - 1} + {6}^{ - 1} + {8}^{ - 1} ) {}^{x} = 1$
Find X ​

Answer 1

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Given:-

${2}^{ - 1} + {4}^{ - 1} + {6}^{ - 1} + {8}^{ - 1} ) {}^{x} = 1$

To Find:-

X

Formula:-

${a} - ^{m} = \frac{1}{ {a}^{m} }$

Solution:-

$( {2} - ^{1} + {4} - ^{1} + {6} - ^{1} {8} - ^{1} x = 1 \\ ( \frac{1}{2} + \frac{1}{4} + \frac{1}{6} + \frac{1}{8} ) x = 1 \\ \frac{12 + 6 + 4 + 3}{24} x = 1 \\ ( \frac{25}{24} x = 1 \\ \\ x = \frac{24}{25}$

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