Question

$(2^{ - 1} \times 4^{ - 1} ) \div 2^{ - 2}$
solve​

Answer 1

Answer:

Step-by-step explanation:

$a^(-n)=\frac{1}{a^n}$

=$(\frac{1}{2} *\frac{1}{4})$÷$\frac{1}{4}$

= $\frac{1}{8}$÷$\frac{1}{4}$

=$\frac{4}{8}$ = $\frac{1}{2}$