Question

${2}^{2} - 5 + 2 = 0$
In complete square method

Answer 1

Hi Mate !!


Here's the solution :-


Given equation :- 2x² - 5x + 2 = 0

• First we divide all the numbers by the coefficient of x² i.e, 2

$\frac{2 {x}^{2} }{2} - \frac{5x}{2} + \frac{2}{2} = 0$

${x}^{2} - \frac{5x}{2} + 1 = 0$

${x}^{2} - 2 \times x \times \frac{5}{4} + { (\frac{5}{4}) }^{2} - ( { \frac{5}{4}) }^{2} + 1 = 0$

$( {x - \frac{5}{4}) }^{2} = - 1 + \frac{25}{16}$


$( {x - \frac{5}{4} )}^{2} = \frac{ - 16 + 25}{16}$


$( {x - \frac{5}{4} )}^{2} = \frac{9}{16}$


$x - \frac{5}{4} = \sqrt{ \frac{9}{16} }$


$x - \frac{5}{4} = + - \frac{ 3}{4}$


$x = \frac{5}{4} + - \frac{3}{4}$
_______________

$x = \frac{5}{4} + \frac{3}{4}$

$x = \frac{8}{4}$

$x = 2$

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$x = \frac{5}{4} - \frac{3}{4}$


$x = \frac{2}{4}$


$x = \frac{1}{2}$


So, the Zeros are :- 2 and 1/2