Question

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$({2}^{3})^{2} \times{2}^{4} \div ({2}^{0} + {3}^{0})^{2}$

Answer 1

$(2^3)^2 \times 2^4 \div (2^0 + 3^0)^2 \\ \\ = 2^{3 \times 2} \times 2^4 \div (1 + 1)^2 \\ \\ = 2^6 \times 2^4 \div 2^2 \\ \\ = 2^{6 + 4 - 2} \\ \\ = 2^{10 - 2} = 2^8 = \bold{256}$

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Answer 2

✔✔heya here is ur answer!!

THANK YOU ✌✌

HOPE IT HELPS YOU ☺☺