Question

$2 551210$
​

Answer 1

Answer:

sorry I didn't know the answer

Step-by-step explanation:

please follow me and thanks me

Answer 2

Answer:

$\frac{ {2}^{32} \div {2}^{28} }{ {3}^{10} \div {3}^{9} } \\ = \frac{ {2}^{32 - 28} }{ {3}^{10 - 9} } \\ = \frac{ {2}^{4} }{ {3}^{1} } \\ = \frac{16}{9}$