![2 ^{5x}÷ 2^ = \sqrt[5]{2^{20} }](https://tex.z-dn.net/?f=2+%5E%7B5x%7D%C3%B7+2%5E++%3D+%5Csqrt%5B5%5D%7B2%5E%7B20%7D+%7D "2 ^{5x}÷ 2^ = \sqrt[5]{2^{20} }")
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Step-by-step explanation:
Given,
2
5x
÷2
x
=
5
20
20
=
2
x
2
5x
=
5
2
20
2
5x−x
=16
2
4x
=2
4
By comparing powers
4x=4
∴x=1
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