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Answer:
Printing mistake .
Real question :
2√2a³ + 16√2b³ + c³ - 12 abc
Now , 2√2 = (√2)³ , 16√2 = (2√2)³
So :
(√2a)³ + (2√2b)³ + c³ - 3×2√2×2 × abc
We know x³+y³+z³ - 3 xyz = (x+y+z)(x²+y²+z²-xy-yz-xz)
= > (√2a+2√2b+c)(2a²+8b²+c²-4ab-2√2bc-√2ac)
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