Math, asked by XxItzAwsomeGirlxX07, 1 month ago


 2 \sin \binom{5\pi}{12}  \times  \cos \binom{7\pi}{12}  =
A) 1/√2
B) -1/2
C) 1/2
D) 1​

Answers

Answered by IIXxSavageSoulxXII
22

 \huge\sf \fbox \pink {solution}

\red{=> \: 2 \div  \frac{1}{2} \times ( \sin(\pi) +  \sin \binom{ - \pi}{6}  }  \\   \red{  => 2  \times  \frac{1}{2}  \times (0 \sin \binom{ - \pi}{6} } \\  \red{ => 2 \times  \frac{1}{2}  \times (0 -  \frac{1}{2} )} \\  \red{ => 2 \times  \frac{1}{2}  \times ( -  \frac{1}{2} )} \\  \red{ => - 2 \times  \frac{1}{2}   \times  \frac{1}{2} } \\  \red{ \cancel{-2} \times  \frac{1}{2 \: this \: is \: cut} \times  -\frac{1}{2}} \\   \green{=> -  \frac{1}{2} }

\bold{∴ Hence,\:option\:B\:is\:correct}

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