Question

$2 sin3x = \sqrt{3}$
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Answer 1

Answer:

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Answer 2

Question :

2 sin 3x = √3

To Find :

The value of x

Solution :

$\tt \: 2 \times \sin3x = \sqrt{3}$

$\tt \: \sin3x = \dfrac{ \sqrt{3} }{2}$

$\tt \: \sin3x = \sin {60}^{ \circ}$

$\because \sf \sin {60}^{ \circ} = \dfrac{ \sqrt{3} }{2}$

$\tt \: 3x = {60}^{ \circ}$

$\tt \: x = \dfrac{ {60}^{ \circ} }{3}$

$\tt \: \red{ \sf \: x = {20}^{ \circ} }$