Question

$2 + \sqrt{2 } + 1 \div 2 \sqrt{2} + 1 \div \sqrt{2} - 2$
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Answer 1

Answer:

$2 + \sqrt{2} + \frac{1}{2 \sqrt{2} } + \frac{1}{2 \sqrt{2} } - 2 \\ \\ = \sqrt{2 } + 2 \times ( \frac{1}{2 \sqrt{2} } ) \\ = \sqrt{2} + \frac{1}{ \sqrt{2} } \\ = \frac{2 + 1}{ \sqrt{2} } \\ = \frac{3}{ \sqrt{2} }$