Factorise
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Answer
We know that,
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
Thus,
2
2
a
3
+8b
3
−27c
3
+18
2
abc
Here, a=
2
a, b=2b and c=−3c
=(
2
a+2b−3c)[(
2
a)
2
+(2b)
2
+(−3c)
2
−
2
a(2b)−(2b)(−3c)−(−3c)(
2
a)]
=(
2
a+2b−3c)(2a
2
+4b
2
+9c
2
−2
2
shubhamjha1111:
i dont understand
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