Math, asked by rajveer2345soni, 7 months ago


2 \sqrt{3} x { }^{2}  - 5x +  \sqrt{3}

Answers

Answered by warylucknow
0

The factors of 2\sqrt{3}x^{2}-5x+\sqrt{3} are (\sqrt{3}x-1)(2x+\sqrt{3}).

Step-by-step explanation:

The expression is:

2\sqrt{3}x^{2}-5x+\sqrt{3}

Factorize the expression as follows:

2\sqrt{3}x^{2}-5x+\sqrt{3}=2\sqrt{3}x^{2}-3x-2x+\sqrt{3}

                            =\sqrt{3}x(2x-\sqrt{3})-1(2x+\sqrt{3})\\=(\sqrt{3}x-1)(2x+\sqrt{3})

Thus, the factors of 2\sqrt{3}x^{2}-5x+\sqrt{3} are (\sqrt{3}x-1)(2x+\sqrt{3}).

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