Question

$2 \sqrt{6 \div \sqrt{2 + \sqrt{3} } }$
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Answer 1

Answer:

$2( \sqrt{6} \div \sqrt{2 + \sqrt{3} } ). \\ \\ = 2( \sqrt{6} \div \sqrt{2 + 1.73} ). \\ \\ = 2( \sqrt{6 \div 1.92} ). \\ \\ = 2 \sqrt{3.125} . \\ \\ = 2 \times 1.56 \\ \\ = 3.125.$

Answer 2

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