Math, asked by Remotey, 1 year ago


2 { \tan(45) }^{2}  +  { \cos(30) }^{2}  -  { \sin(60) }^{2}

Answers

Answered by sijasubbiah
0

Hey

Here is your answer,

= 2 tan^2 45° + cos^2 30° - sin^2 60°

Substitute the values of the given degrees of trigonometric functions.

= 2 (1)^2 + (√3/2)^2 - (√3/2)^2
= 2 x 1
= 2

Hope it helps you!

Answered by Anonymous
4
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The answer of u r question is....

Is in the pic.
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