Question

$2 \times 2 - 2x + \frac{1}{2} = 0$
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Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

$2 \times 2 - 2x + \frac{1}{2} = 0$

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > 2 \times 2 - 2x + \frac{1}{2} = 0$

$= > 4 - 2x + \frac{1}{2} = 0$

$= > - 2x + \frac{1}{2} + 4 = 0$

=>L.C.M IS 2

$= > \frac{ - 2x \times 2 + 1 + 4 \times 2}{2}$

$= > \frac{ - 4x + 1 + 8}{2} = 0$

$= > \frac{ - 4x + 9}{2 } = 0$

$= > - 4x + 9 = 0$

$= > - 4x = - 9$

=>Here,- us on both sides then it will be cancelled:-

$= > 4x = 9$

$\bold{\red{= > x = \frac{9}{4} }}$

$\huge\mathcal{ check: }$

$= > 2 \times 2 - 2x + \frac{1}{2} = 0$

$= > 4 - 2 \times \frac{9}{4} + \frac{1}{2} = 0$

$= > 4 - \frac{9}{2} + \frac{1}{2} = 0$

$= > \frac{8 - 9 + 1}{2} = 0$

$= > \frac{ - 1 + 1}{2} = 0$

$= > \frac{0}{2} = 0$

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