Question

$2 \times {}^{2} + 4 \times + 5 = 0$
Find the root of the following quadratic equation

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Answer 1

Given :x2+ 4x- 5 = 0

⇒x2+ 2 ×x× 2 - 5 = 0

⇒x2+ 2 ×x× 2 - 5 + 22- 22= 0

⇒x2+ 2 ×x× 2 + 22- 5 - 4 = 0

⇒ (x+ 2)2- 9 = 0

⇒ (x+ 2)2= 9

⇒ (x+ 2) = √9 = ±3

⇒x= -2 ± 3 = -2+ 3 or -2 - 3 = 1 or -5

It is not 2x^2 ,, it will be x^2

Answer 2

no real roots exists

as, Discriminant is less than 0