Question

$(2^{x-1}*4^{x+1})/8^{x-1})=64$

Answer 1

Answer:

x=4/3

Step-by-step explanation:

pl correct qn as:

(2ˣ⁻¹*4ˣ⁺¹) *8ˣ⁻¹=64

(2ˣ⁻¹(2)²ˣ⁺² * (2³*⁽ˣ⁻¹⁾=(2³)²

2⁽ˣ⁻¹⁺²ˣ⁺²⁾ *2³ₓ⁻³ =2⁶

2^(3x+1)* 2^(3x-3)=2^6

2^(3x+1+3x-3)=2^6

2^(6x-2)=2^6

6x-2=6

6x=8

x=8/6=4/3