Question

${2}^{x - 1} = \frac{1}{ {8}^{x - 3} }$
find the value of x​

Answer 1

Step-by-step explanation:

${2}^{x - 1} = \frac{1}{ {8}^{x - 3} }$

${2}^{x - 1} = \frac{1}{ { {2}^{3} }^{(x - 3)} } \\ as \: 8 = {2}^{3}$

this can be written as

${2}^{x - 1} = \frac{1}{ { {2}^{3} }^{(x - 3)} }$

$cross \: multiplication \: \frac{a}{b} = \frac{c}{d} \: then \: a \times d = b \times c$

here

a ={2}^{x - 1},b=1,c=1,d={2^3}^{x - 3}