Math, asked by madhav6773, 1 year ago


2 {x}^{2}  +17 x + 8

Answers

Answered by Anonymous
8
Hey !!! ^_^

Here is your answer

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 {2x}^{2}  + 17x + 8 \\  \\  {2x}^{2} + 16x + x + 8 \\  \\ 2x(x + 8) + 1(x + 8) \\  \\ (x + 8) (2x + 1) \\  \\
I HOPE IT WILL HELP YOU.


Thank you

☺️
Answered by Divyaalia
8

2 {x}^{2}  + 17x + 8 \\ 2 {x}^{2}  + (16 + 1)x + 8 \\ 2 {x}^{2}  + 16x + x + 8 \\ 2x(x + 8) +  1(x + 8) \\ (2x + 1)(x + 8)
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