Question

$2 {x}^{2} - 27$

Answer 1

Step-by-step explanation:

$\pink{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}$ $\red{\bold{\underline{\underline{QUESTION:-}}}}$ Q:- $2 {x}^{2} - 27$ $\huge\tt\underline\blue{Answer }$ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️ ════════════XXX═════════════ $⟹ 2 {x}^{2} - 27$ $⟹ { (\sqrt{2x} )}^{2} - {(3 \sqrt{3} )}^{2}$ It is the form of a^2-b^2 $⟹ {a}^{2} - {b}^{2} = (a + b)(a - b)$ $⟹ So, {( \sqrt{2x} )}^{2} - {(3 \sqrt{3}) }^{2} = ( \sqrt{2}x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$ $∴2 {x}^{2} - 27 = ( \sqrt{2} x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$ ════════════XXX═════════════ HOPE IT HELPS YOU

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Thankyou:)

Answer 2

Step-by-step explanation:

$⟹\sf {( \sqrt{2x} )}^{2} - {(3 \sqrt{3}) }^{2} = ( \sqrt{2}x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$ $\sf 2 {x}^{2} - 27 = ( \sqrt{2} x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$