Question

$(2 {x}^{2} - 3)and \: ( - 3 + {y}^{3} + 2x)multiply \: the \: following$
please multiply the following

Answer 1

$\large \tt AHOY!! \:$
given (2x² - 3) and (-3 + y³ + 2x)

= (2x² - 3)(-3 + y³ + 2x)

= [(2x² × -3) + (2x² × y³) + (2x² × 2x)] - [(3 × -3) + (3 × y³) + (3 × 2x)]

= (-6x² + 2x²y³ + 4x³) - (-9 + 3y³ + 6x)

= -6x² + 2x²y³ + 4x³ + 9 - 3y³ - 6x

$\large \tt HOPE \: THIS \: HELPS!!$

Answer 2

$\red {\huge{answer}}$
6x² + 2x²y³ + 4x³ + 9 - 3y³ - 6x.


$\green{soulution}$
Step by step deviation ,


= (2x² - 3)(-3 + y³ + 2x)

Multiply

First time

2x² to -3 + y³ + 2x.

Again ,

we multiply

- 3 to -3 + y³ + 2x.

Now we proceed step by step deviation.


=>> [(2x² × -3+ 2x² × y³ + 2x² × 2x)] - [(3 × -3+ 3 × y³ + 3 × 2x)]


= >> (-6x² + 2x²y³ + 4x³) - (-9 + 3y³ + 6x)

Note some minor point .

[ +×+= + , - × - = + , + × - = + ]

=>> -6x² + 2x²y³ + 4x³ + 9 - 3y³ - 6x.


Therefore the answer is (-6x² + 2x²y³ + 4x³ + 9 - 3y³ - 6x.)



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