![2 {x }^{2} + 5x \div 3 - 2 = 0 2 {x }^{2} + 5x \div 3 - 2 = 0](https://tex.z-dn.net/?f=2+%7Bx+%7D%5E%7B2%7D+%2B+5x+%5Cdiv+3+-+2+%3D+0+)
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Answer:
x=3/2 , 2/3
Step-by-step explanation:
2x²+5x÷3-2=0
2x²+5x/3-2=0
multiplying both sides of equation by 3, we get
6x²+5x-6=0
6x²+9x-4x-6=0
3x(2x+3)-2(2x+3)=0
(2x+3)(3x-2)=0
(2x+3)=0 (3x-2)=0
2x=3 3x=2
x=3/2 x=2/3
please mark my answer as brainliest.
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