Question

$2 {x}^{2} - 7x + 3 = 0$
by completing square

Answer 1

2x^2-7x+3=0
dividing the equation by coefficient of x^2
2x^2/2-7x/2+3/2=0
x^2-7x/2=-3/2
completing square on the left side
(x^2-2*(-7x/2))+49/16=-3/2
balancing on the right side
(x-7/4)^2=-3/2+49/16
(x-7/4)^2=25/16
taking underroot on the right side
(x-7/4)=+-5/4
x=7/4+-5/4
x=3 or 1/2

hope it helps you