Math, asked by sindhursa, 7 months ago

$2 { {x }^{2} } - \sqrt{3x} + 1 = 0$

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Answered by Anonymous

1

Answer:

what do we have to do dear ❣️

Answered by shivyakikloo

3

Answer:

$2 { {x }^{2} } - \sqrt{3x} + 1 = 0$

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