Question

$(2 {x}^{3} - 4 {x}^{2} - 6x + 8) \div 2x$
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Answer 1

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Answer 2

Answer:

$x^{2} -2x-3+\frac{4}{x}$

Step-by-step explanation:

$\frac{(2x^{3} -4x^{2} -6x+8)}{2x}$

dividing individually,

we get

$\frac{2x^{3} }{2x}-\frac{4x^{2} }{2x}-\frac{6x}{2x}+\frac{8}{2x}$

On simplifying,

$x^{2} -2x-3+\frac{4}{x}$ is required solution.