find values of x satisfying this equation .
Answers
Answer:
sin
−1
cos(
x
2
+5x+3
2x
2
+10x+4
)=cot(cot
−1
(
9x
2−18x
))+
2
π
⇒sin
−1
sin(
2
π
−(
x
2
+5x+3
2x
2
+10x+4
))=
9x
2−18x
+
2
π
⇒
2
π
−
x
2
+5x+3
2x
2
+10x+4
=
9x
2−18x
+
2
π
⇒−18x
3
−90x
2
−36x=2x
2
+10x+6−18x
3
−90x−54x
⇒2x
2
−8x+6=0⇒x
2
−4+3=0⇒(x−1)(x−3)=0
Therefore product of roots is 1×3=3
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Related Questions to study
Inverse circular functions,Principal values of sin
−1
x,cos
−1
x,tan
−1
x.
tan
−1
x+tan
−1
y=tan
−1
1−xy
x+y
, xy<1
π+tan
−1
1−xy
x+y
, xy>1.
(a) tan
−1
m
2
−n
2
2mn
+tan
−1
p
2
−q
2
2pq
=tan
−1
M
2
−N
2
2MN
where M=mp−nq,N=np+mq
(b)
3
2
tan
−1
n
3
−3m
2
n
3mn
2
−m
3
+
3
2
tan
−1
q
3
−3p
2
q
3pq
2
−p
3
=tan
−1
M
2
−N
2
2MN
Where M=−mp+nq,N=np+mq and all the letters are +ive quantities.
Study later
View solution
2tan
−1
(
1−x
1+x
)+sin
−1
(
1+x
2
1−x
2
)= 3