Math, asked by TheBrainlyMan, 8 months ago


2  {}^{x}  \times 2 {}^{x - 1 }   \div 2 {}^{x + 1}  \times 2 {}^{x}
Solve it ​

Answers

Answered by mitali190
1

Answer:

By using BODMAS

 {2}^{x}  \times  {2}^{x - 1} \div  {2}^{x + 1}  \times  {2}^{x}

2^X × 2^X-1 / 2^X+1 × 2^X

2^X-1 ÷ 2^X+1

IF BASE HAVE DIVIDED SIGH AND ARE SAME AND

POWER IS DIFFERENT THEN POWER WILL BE SUBTRACT

2^X-1-(X+1)

2^X-1-X-1

2^X-X-1-1

2^-1-1

2^-2

1/4

0.25

ANSWER

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