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Answer:
By using BODMAS
2^X × 2^X-1 / 2^X+1 × 2^X
2^X-1 ÷ 2^X+1
IF BASE HAVE DIVIDED SIGH AND ARE SAME AND
POWER IS DIFFERENT THEN POWER WILL BE SUBTRACT
2^X-1-(X+1)
2^X-1-X-1
2^X-X-1-1
2^-1-1
2^-2
1/4
0.25
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