Question

${2}^{x + y} \: = \: {2}^{x - y} \: = \: \sqrt{8}$
Then the value of y is
a) none of these
b) 0
c) 3/2
d) 1/2

please writ the correct answer only or else i will report ​

Answer 1

Answer:

3/2

Step-by-step explanation:

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Answer 2

ANSWER:

b) 0

STEP-BY-STEP EXPLANATION:

Given 2^(x + y) = 2^(x - y) = √8. We need to find out the value of y.

Now, we can write √8 as 2√2. [ because 2√2 = √(2 × 2 × 2) = √8 ]

So,

→ 2^(x + y) = 2^(x - y) = 2√2

Further √2 can be written as 2½.

→ 2^(x + y) = 2^(x - y) = 2 × 2½

Since, we need to find the value of y, we can find that using by first to equivalent i.e. 2^(x + y) = 2^(x - y) So, let's take 2^(x + y) = 2^(x - y) to find the value of y.

→ 2^(x + y) = 2^(x - y)

As 2 is common among them. So, 2 is throughout cancel. We left with,

→ x + y = x - y

Take x terms on one side and y terms on other side,

→ x - x = - y - y

→ 0 = -2y

→ y = 0

Therefore, the value of y is 0.