Question

$2( {y}^{2} - 6y) \times ({y}^{2} - 6y) - 8( {y}^{2} - 6y + 3) - 40 = 0$
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Answer 1

2(y sq-6y)*(y sq-6y)-8(y sq-6y+3)-40 =0

2(y sq+y sq-y sq)(-6y-6y+6y)-8-3-40=0

2-y sq * -6y -51=0

2-y sq*-6y=0+51

2-y sq*-6y =51

Answer 2

Step-by-step explanation:

Answer is in the pic.

hope it will help you !