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21c^{3}  - 5c^{2}d  - 3c {d}^{2}  - 2 {d}^{3}  \div 7  {c}^{2}  + 3cd + d ^{2}

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Answered by iniko
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Middle SchoolMathematics 5 points

(3c^2 −5cd+d^2 )−(7c^2 +4cd−9d^2 )

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Answered by

mathstudent55

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(3c^2 − 5cd + d^2) − (7c^2 + 4cd − 9d^2) =

1. Drop the parentheses around the first polynomial since they are not needed.

= 3c^2 − 5cd + d^2 − (7c^2 + 4cd − 9d^2)

2. To drop the parentheses around the second polynomial, every sign inside changes.

= 3c^2 − 5cd + d^2 − 7c^2 - 4cd + 9d^2

3. Combine like terms. Like terms have the same variables and exponents.

= 3c^2 - 7c^2 - 5cd - 4cd + d^2 + 9d^2

= -4c^2 - 9cd + 10d^2

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