Question

$23336y { \frac{ \leqslant ? \times \frac{?}{?} }{?} }^{?}$
pagal​

Answer 1

Answer

Step by step explanation

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Answer 2

Answer:

Question No 1 :-

Using the Pythagorean Theorem to answer this question.

Becca paddles a boat from the south bank of a stream to the north bank. She paddles at a rate of 8 mph. The stream is flowing west at a rate of 6 mph. What is Becca's velocity.

Given :-

Becca paddles a boat from the south bank of a stream to the north bank.

She paddles at a rate of 8 mph. The stream is flowing west at a rate of 6 mph.

To Find :-

What is the Becca's velocity.

Formula Used :-

$\clubsuit$ Pythagorean Theorem :

$\mapsto \sf\boxed{\bold{\pink{(Perpendicular)^2 + (Base)^2 =\: (Hypotenuse)^2}}}$

Solution :-

Given :

$\bigstar\: \: \sf Perpendicular =\: 8\: mph$

$\bigstar\: \sf Base =\: 6\: mph$

According to the question by using the pythagorean theorem we get,

$\longrightarrow \sf (8)^2 + (6)^2 =\: (Hypotenuse)^2$

$\longrightarrow \sf 8 \times 8 + 6 \times 6 =\: (Hypotenuse)^2$

$\longrightarrow \sf 64 + 36 =\: (Hypotenuse)^2$

$\longrightarrow \sf 100 =\: (Hypotenuse)^2$

$\longrightarrow \sf \sqrt{100} =\: Hypotenuse$

$\longrightarrow \sf 10 =\: Hypotenuse$

$\longrightarrow \sf\bold{\red{Hypotenuse =\: 10\: mph}}$

$\therefore$ The actual velocity is 10 mph .

Question No - 2 :-

Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 metres. Then Andrew kicks the ball straight back. The ball rolls back along the same path for 9.5 metres. What is the distance did the ball travel.

Given :-

Andrew kicks a ball along a straight path. The ball straight forward for 13.2 metres. Then Andrew kicks the ball straight back. The ball rolls back along the same path for 9.5 metres.

To Find :-

What is the distance did the ball travel.

Solution :-

$\mapsto$ First, Andrew kicks a ball along a straight path. The ball straight forward 13.2 metres.

$\mapsto$ Again, Andrew kicks the ball straight back. The ball rolls back along the same path for 9.5 metres.

Then, the distance did the ball travel is :

$\longrightarrow \sf Distance\: travel\: by\: the\: ball =\: 13.2\: metres + 9.5\: metres$

$\longrightarrow \sf Distance\: travel\: by\: the\: ball =\: \dfrac{132}{10}\: + \dfrac{95}{10}\: metres$

$\longrightarrow \sf Distance\: travel\: by\: the\: ball =\: \dfrac{132 + 95}{10}\: metres$

$\longrightarrow \sf Distance\: travel\: by\: the\: ball =\: \dfrac{227}{10}\: metres$

$\longrightarrow \sf\bold{\red{Distance\: travel\: by\: the\: ball =\: 22.7\: metres}}$

$\therefore$ The distance travel by the ball is 22.7 m .