Question

${24}^{2x} - {7}^{x}. {(3 + 4)}^{x} = 0$
solve it please... ​

Answer 1

${24}^{2x} - {7}^{x}. {(3 + 4)}^{x} = 0$

$24 ^{2x} - 7 ^{x} \times 7 ^{x} = 0$

$24 ^{2x} - 7 ^{2x} = 0$

$24 ^{2x} = 7 ^{2x}$

$( \frac{24}{7} ) ^{2x} = 1$

$( \frac{24}{7} ) ^{2x} = ( \frac{24}{7} ) {}^{0}$

$2x = 0$

$x = 0$

Answer 2

Answer:

Given,

24^2x - 7^x . ( 3 + 4 )^x = 0.

$= 24 {}^{2x} - 7 {}^{x} .7 {}^{x} = 0. \\ = 24 {}^{2x} - 7 {}^{2x} = 0. \\ = ( \frac{24}{7} ) {}^{2x} = 1. \\ = ( \frac{24}{7} ) {}^{2x} = ( \frac{24}{7} ) {}^{2x} . \\ = 2x = 2x. \: \: \: \: \: \: \: \: ( \frac{24}{7} \: is \: cut \: from \: both \\ the \: sides) \\ = x {}^{2} = 2 \times 2. \\ = x {}^{2} = 4. \\ = x = \sqrt{4} . \\ x = 2.$