Question

$24x^{2} - 41x + 12 = 0$
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Answer 1

24x^{2} - 41x + 12 = 0

$24 {x}^{2} - 41x = - 12$

${x}^{2} - 41x = \frac{ - 12}{24}$

${x}^{2} - 41x = - \frac{1}{2}$

${x}^{2} - x = - \frac{1}{2 \times 41}$

${x}^{2} - x = - \frac{1}{82}$

Can't solve any further.

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Answer 2

Question :-

Find x in 24x² - 41x + 12 = 0

By using Splitting the middle term method, let us factorize 24x² - 41x + 12

24x² - 32x - 9x + 12 = 0

☞ 8x(3x - 4) - 3(3x - 4) = 0

☞ (3x - 4)(8x - 3) = 0

x can have 2 values here,

1st value :-

3x - 4 = 0

☞ 3x = 4

☞ x = $\dfrac{4}{3}$

2nd value :-

8x - 3 = 0

☞ 8x = 3

☞ x  = $\dfrac{3}{8}$

Hope it helps!

Happy day!