![25 {}^{x - 1} = 5 {}^{2x - 1} - 100 25 {}^{x - 1} = 5 {}^{2x - 1} - 100](https://tex.z-dn.net/?f=25++%7B%7D%5E%7Bx+-+1%7D++%3D+5+%7B%7D%5E%7B2x+-+1%7D++-+100)
hi guys
please
solve..
Merry Christmas for all my friends. ..
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Hlo
wish u and ur family A very happy merry Christmas
I HOPE IT WILL HELP YOU DEAR
THANKU
wish u and ur family A very happy merry Christmas
I HOPE IT WILL HELP YOU DEAR
THANKU
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25^x-1 = 5^2x-1 -100
5^2 x-2 = 5^2x -1 -100
5^2x -2 -5^2 x-1 = -100
5^2x-2( 1 - 5) = -100
5^2x-2= -100/-4
5^2x-2 = 25
5^2x-2= 5^2
compare
2x-2 = 2
2x = 4
x= 2
5^2 x-2 = 5^2x -1 -100
5^2x -2 -5^2 x-1 = -100
5^2x-2( 1 - 5) = -100
5^2x-2= -100/-4
5^2x-2 = 25
5^2x-2= 5^2
compare
2x-2 = 2
2x = 4
x= 2
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