Question

$27 \ \frac{1}{3} \times 16 \ \frac{ - 1}{4}$
simplify
formula
${x}^{a} \times {x}^{b} = {x}^{a} + {b}$
​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

${27}^{ \frac{1}{3} } \times {16}^{ \frac{ - 1}{4} }$

$= {( {3}^{3} )}^{ \frac{1}{3} } \times {( {2}^{4}) }^{ \frac{ - 1}{4} }$

$= {3}^{3 \times \frac{1}{3} } \times {2}^{4 \times \frac{ - 1}{4} }$

$= 3 \times {2}^{ - 1}$

$= \frac{3}{2}$

Answer