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Step-by-step explanation:
Lets write the equation according to the question.
27^x-1 = 9^x+2
We can reduce the numbers 27 and 9 to base 3.
3^ 3(x-1) = 3^2(x-2) [ 27 = 3^3 and 9 = 3^2 . The exponents are multiplied to the existing exponents.]
3^3x-3 = 3^2x + 2
Now , as the bases of the RHS and LHS have matched , we will remove the base.
3x-3 = 2x+4.
3x-2x = 4+3= 7 [Using transposition]
Hence , x = 7.
Hope it helps.
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