Question

$27 {x}^{3} + 64 {y}^{3} - 125 {z}^{3} + 180xyz$
factorise using the formula:-
${a}^{3} + {b}^{3} + {c}^{3} - 3abc$

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Answer 1

Step-by-step explanation:

$\sf\ {27x}^{3} + {64y}^{3} - {125z}^{3} + 180xyz \\ \\ \sf\ \implies: {(3x)}^{3} + {(4y)}^{3} + {( - 5z)}^{3} + 3 \times 3x \times 4y \times - 5z \\ \\ \sf\ \implies: {(3x)}^{3} + {(4y)}^{3} + {( - 5z)}^{3} - 180xyz$