Question

$27a {3}^{2} + b {}^{3 } + c {}^{3} - 9abc$
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Answer 1

Step-by-step explanation:

$27a {3}^{2} + b {}^{3 } + c {}^{3} - 9abc$

=(3a)³+b³+c³-3(3a)BC

=(3a+b+c)(9a²+b²+c²-3ab-bc-3ca)