Question

$27x ^3 - 1 \div 216 - 9 \\div 2x ^2 + 1 \div 4x$

Answer 1

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27x^3-1/216-9/2x^2+1/4x
=(3x)^3+(-1/6)^3+3×3x×3x×(-1/6)+3×3x×(-1/6)×(-1/6)
(a+b)^3=a^3+b^3+3a^2b+3ab^2
=(3x-1/6)^3
Hence factorized......

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