Question

$(2a + 3b) {}^{2} - 25c { }^{2}$
FACTORIZATION

Answer 1

HEY MATE HERE IS UR ANSWER

$(2a + 3b)^{2} - {5c}^{2}$

$now \: by \: using \: \: identity \: \: {a}^{2} - {b}^{2} = \: (a + b)(a - b) \:$

$here \: (a) = 2a + 3b \: \: \: and \: \:( b) \: = 5c$
$now \: we \: \: have \:$
$(2a + 3b - 5c)(2a + 3b + 5c)$

$hence \: this \: is \: the \: required \: factorized \: form \:$

$\bf{HOPE\:ITS\:HELPFUL\:IF\:YES\:PLEASE\:MARK\:AS\:BRAINLIEST}[\tex] [tex] by \: nipun \:$

Answer 2

Given:

(2a+3b)²-25c²

==> (2a+3b)²-(5c)²

We know that a²-b²=(a+b)(a-b)

so a = 2a+3b

and b = 5c

==>(2a+3b+5c)(2a+3b-5c)

That's the answer

Hope it helps you

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