Question

$(2a + 3b) {}^{2} - 4c {}^{2}$
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Answer 1

$\bold \red{(2a + 3b)^{2} - 4c ^{2}}$

$\bold \red{= (2a + 3b) ^{2} - (2c) ^{2} }$

$\bold \red{= [(2a + 3b) + 2c] \: [(2a + 3b) - 2c]}$

$\bold \red{ = (2a + 3b + 2c) \: (2a + 3b - 2c)}$

$\bold \red{We \: have \: used \: the \: identify,}$

$\bold \red{ {x}^{2} - {y}^{2} = (x + y) \: (x - y)}$

$\bold \red{Here, \: (2a + 3b) = x \: and \: 2c = y}$

Answer 2

Hope it will be helpful to you