Question

$(2a + b) ^{2} - 6a - 3b - 4$
please factorize this question

Answer 1

Here is your answer buddy ,

(2a+b)^2 -6a-3b-4
= 4a^2+b^2+4ab-6a-3b-4
= 2a(2a-3)+b(b-3)-4(ab-1)

Hope this helps you.
Be Brainly.

Answer 2

Given Equation is (2a + b)^2 - 6a - 3b - 4.

It can be written as:

⇒ (2a)^2 + (b)^2 + 2(2a)(b) - 6a - 3b - 4

⇒ 4a^2 + b^2 + 4ab - 6a - 3b - 4

⇒ 4a^2 + b^2 + 2ab + 2ab + 2a - 8a + b - 4b - 4

⇒ 4a^2 + 2ab + 2a + 2ab + b^2 + b - 8a - 4b - 4

⇒ 2a(2a + b + 1) + b(2a + b + 1) - 4(2a + b + 1)

⇒ (2a + b - 4)(2a + b + 1).

Therefore, factorization of (2a + b)^2 - 6a - 3b - 4 = (2a + b - 4)(2a + b + 1).

Hope this helps!