Question

$( 2a \div b ) \times y = ({a}^{2} \div {b}^{2}) + 1$
where
a
and b
are
where a' and 'b' are integers
Find y​

Answer 1

Step-by-step explanation:

$( \frac{2a}{b} )y = \frac{ {a}^{2} }{ {b}^{2} } + 1 \\ \frac{2ay}{b} = \frac{ {a}^{2} }{ {b}^{2} } + 1 \\ \frac{2ay}{b} - \frac{ {a}^{2} }{ {b}^{2} } = 1 \\ \frac{2aby - {a}^{2} }{ {b}^{2} } = 1 \\ 2aby - {a}^{2} = {b}^{2} \\ 2aby = {a }^{2} + {b}^{2} \\ \boxed{y = \frac{{a }^{2} + {b}^{2} }{2ab}}$